Dental Crown Cost in Indiana (2026)
A dental crown in Indiana averages $1,230 (2026). Crowns cap damaged teeth or complete the visible portion of an implant.
Dental Implant Cost Calculator
Estimated cost in Indiana
$1,760 – $6,780
Average: $3,870
Includes implant, abutment, and crown where applicable. Actual quotes vary by provider.
| Procedure | Low | Average | High |
|---|---|---|---|
| Single implant | $1,060 | $2,640 | $4,840 |
| All-on-4 (full arch) | $10,560 | $19,360 | $30,800 |
| Crown (per tooth) | $700 | $1,230 | $1,940 |
| Bone graft (if needed) | $350 | $700 | $1,320 |
Indiana vs. national average (single implant): national mid $3,000. Last updated: 2026-03-01.
Pricing in Indiana
Prices in major metros like Indiana's largest cities may run 10–20% above state averages.
Estimates based on ADA survey data, regional dental fee reports, and 2026 market adjustments.
Frequently Asked Questions
How much does crown cost in Indiana?
In Indiana, typical range is $700–$1,940, averaging $1,230 in 2026.
Is this included in implant quotes?
Some providers bundle procedures; always request an itemized estimate before treatment.