All-on-4 Dental Implants Cost in St. Petersburg, FL (2026)
All-on-4 in St. Petersburg, FL averages $22,210 per arch ($12,110 – $35,330). Metro-adjusted pricing for St. Petersburg. Use the calculator below for a personalized estimate.
Dental Implant Cost Calculator
Estimated cost in Florida
$1,960 – $7,550
Average: $4,310
Includes implant, abutment, and crown where applicable. Actual quotes vary by provider.
All-on-4 Price Breakdown in St. Petersburg, FL
- Four titanium implants: $5,553 – $8,884
- Fixed full-arch prosthesis: $9,995 – $14,437
- Extractions, sedation, temporaries: $800 – $3,500
Estimates based on ADA survey data, regional dental fee reports, and 2026 market adjustments.
| Procedure | Low | Average | High |
|---|---|---|---|
| Single implant | $1,220 | $3,030 | $5,550 |
| All-on-4 (full arch) | $12,110 | $22,210 | $35,330 |
| Crown (per tooth) | $800 | $1,410 | $2,220 |
| Bone graft (if needed) | $400 | $800 | $1,510 |
St. Petersburg, FL vs. national average (single implant): national mid $3,000. Last updated: 2026-03-01.
Frequently Asked Questions
How much does All-on-4 cost in St. Petersburg, FL?
In St. Petersburg, FL, All-on-4 typically ranges from $12,110 to $35,330, averaging $22,210 per arch in 2026.
Does insurance cover All-on-4?
Most dental plans classify All-on-4 as major restorative work. Coverage is often limited to annual maximums ($1,000–$2,500) unless medically necessary.
Is All-on-4 cheaper than individual implants?
For a full arch, All-on-4 is usually less expensive than placing 8–10 individual implants with separate crowns.